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Question #20
Medium
•
SSC CGL Tier 1 2024
•
25/09/2024, 12:30 PM
•
Trigonometry
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If
cot
2
θ
−
2
cos
2
θ
=
0
\cot^2 \theta - 2 \cos^2 \theta = 0
cot
2
θ
−
2
cos
2
θ
=
0
,
(
0
°
<
θ
<
90
°
)
(0° < \theta < 90°)
(
0°
<
θ
<
90°
)
, then the value of
θ
\theta
θ
is:
A
1. 45°
B
2. 30°
C
3. 90°
D
4. 60°
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Question: If $\cot^2 \theta - 2 \cos^2 \theta = 0$, $(0° < \... - PrepLeague