Question #53
Medium•SSC CGL 2024•Tier 1•Geometry
The side BCBC of △ABC\triangle ABC is produced to point DD. If AC=BCAC=BC and ∠BAC=70∘\angle BAC=70^\circ, find 2.5∠ACD−1.5∠ABC2.5\angle ACD-1.5\angle ABC.
A
235∘235^\circ
B
245∘245^\circ
C
225∘225^\circ
D
230∘230^\circ
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