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Question #64
Medium
•
SSC CGL 2024
•
Tier 1
•
Trigonometry
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If
p
=
sin
A
1
+
cos
A
p=\dfrac{\sin A}{1+\cos A}
p
=
1
+
cos
A
sin
A
, then
sin
A
1
−
cos
A
\dfrac{\sin A}{1-\cos A}
1
−
cos
A
sin
A
equals:
A
p
−
1
p-1
p
−
1
B
1
p
\dfrac{1}{p}
p
1
C
1
1
−
p
\dfrac{1}{1-p}
1
−
p
1
D
1
p
+
1
\dfrac{1}{p+1}
p
+
1
1
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Question: If $p=\dfrac{\sin A}{1+\cos A}$, then $\dfrac{\sin... - PrepLeague