Back
Timer
Enable Timer
No Previous
End of List
Question #64
Medium
•
SSC CGL 2024
•
Tier 1
•
Trigonometry
Bookmark Question
Report Question
If
p
=
sin
A
1
+
cos
A
p=\dfrac{\sin A}{1+\cos A}
p
=
1
+
cos
A
sin
A
, then
sin
A
1
−
cos
A
\dfrac{\sin A}{1-\cos A}
1
−
cos
A
sin
A
equals:
A
p
−
1
p-1
p
−
1
B
1
p
\dfrac{1}{p}
p
1
C
1
1
−
p
\dfrac{1}{1-p}
1
−
p
1
D
1
p
+
1
\dfrac{1}{p+1}
p
+
1
1
Submit Answer
Clear
1
-
4
select •
Enter
submit •
⌫
clear