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Question #75
Easy
•
SSC CGL 2024
•
Tier 1
•
Trigonometry
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In right triangle
A
B
C
ABC
A
BC
(right-angled at
B
B
B
), if
tan
C
=
3
\tan C=\sqrt3
tan
C
=
3
, find
sin
2
C
+
cos
2
C
cosec
2
C
\dfrac{\sin^2 C+\cos^2 C}{\cosec^2 C}
cosec
2
C
sin
2
C
+
cos
2
C
.
A
16
3
\dfrac{16}{3}
3
16
B
3
4
\dfrac{3}{4}
4
3
C
3
16
\dfrac{3}{16}
16
3
D
4
15
\dfrac{4}{15}
15
4
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