Back
Timer
Enable Timer
No Previous
End of List
Question #88
Medium
•
SSC CGL 2024
•
Tier 1
•
Trigonometry
Bookmark Question
Report Question
If
x
=
a
sec
θ
cos
ϕ
x = a\sec\theta\cos\phi
x
=
a
sec
θ
cos
ϕ
,
y
=
b
sec
θ
sin
ϕ
y = b\sec\theta\sin\phi
y
=
b
sec
θ
sin
ϕ
and
z
=
c
tan
θ
z = c\tan\theta
z
=
c
tan
θ
, then the value of
(
x
2
a
2
+
y
2
b
2
−
z
2
c
2
)
\left(\frac{x^2}{a^2} + \frac{y^2}{b^2} - \frac{z^2}{c^2}\right)
(
a
2
x
2
+
b
2
y
2
−
c
2
z
2
)
is equal to:
A
1.0
1. 0
1.0
B
2.3
2. 3
2.3
C
3.1
3. 1
3.1
D
4.2
4. 2
4.2
Submit Answer
Clear
1
-
4
select •
Enter
submit •
⌫
clear